Solve {l}{y=x^2-x+1}{x=4/3}

$$\left\{ \begin{array} { l } { y = x ^ { 2 } - x + 1 } \\ { x = \frac { 4 } { 3 } } \end{array} \right.$$

Solve for y, x

$$x = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333$$

$$y = \frac{13}{9} = 1\frac{4}{9} \approx 1.444444444$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=\left(\frac{4}{3}\right)^{2}-\frac{4}{3}+1$$

Calculate \frac{4}{3} to the power of 2 and get \frac{16}{9}.

$$y=\frac{16}{9}-\frac{4}{3}+1$$

Subtract \frac{4}{3} from \frac{16}{9} to get \frac{4}{9}.

$$y=\frac{4}{9}+1$$

Add \frac{4}{9} and 1 to get \frac{13}{9}.

$$y=\frac{13}{9}$$

The system is now solved.

$$y=\frac{13}{9} x=\frac{4}{3}$$