\left\{ \begin{array} { l } { y = 6 x ^ { 2 } + 7 x - 3 } \\ { x = 7 } \end{array} \right.
Solve for y, x
x=7
y=340
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y=6\times 7^{2}+7\times 7-3
Consider the first equation. Insert the known values of variables into the equation.
y=6\times 49+7\times 7-3
Calculate 7 to the power of 2 and get 49.
y=294+7\times 7-3
Multiply 6 and 49 to get 294.
y=294+49-3
Multiply 7 and 7 to get 49.
y=343-3
Add 294 and 49 to get 343.
y=340
Subtract 3 from 343 to get 340.
y=340 x=7
The system is now solved.
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