\left\{ \begin{array} { l } { y = 4 x + 2 } \\ { y = 10 } \end{array} \right.
Solve for y, x
x=2
y=10
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\left\{ \begin{array} { l } { y = 4 x + 2 } \\ { y = 10 } \end{array} \right.
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10=4x+2
Consider the first equation. Insert the known values of variables into the equation.
4x+2=10
Swap sides so that all variable terms are on the left hand side.
4x=10-2
Subtract 2 from both sides.
4x=8
Subtract 2 from 10 to get 8.
x=\frac{8}{4}
Divide both sides by 4.
x=2
Divide 8 by 4 to get 2.
y=10 x=2
The system is now solved.
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