\left\{ \begin{array} { l } { y = 3 x + 5 - 0.06 x ^ { 2 } } \\ { x = 1 } \end{array} \right.
Solve for y, x
x=1
y=7.94
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y=3\times 1+5-0.06\times 1^{2}
Consider the first equation. Insert the known values of variables into the equation.
y=3+5-0.06\times 1^{2}
Multiply 3 and 1 to get 3.
y=8-0.06\times 1^{2}
Add 3 and 5 to get 8.
y=8-0.06
Calculate 1 to the power of 2 and get 1.
y=7.94
Subtract 0.06 from 8 to get 7.94.
y=7.94 x=1
The system is now solved.
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