Solve {l}{y=3}{y=-x+4}

$$\left\{ \begin{array} { l } { y = 3 } \\ { y = - x + 4 } \end{array} \right.$$

Solve for y, x

$$x=1$$

$$y=3$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$3=-x+4$$

Swap sides so that all variable terms are on the left hand side.

$$-x+4=3$$

Subtract 4 from both sides.

$$-x=3-4$$

Subtract 4 from 3 to get -1.

$$-x=-1$$

Divide both sides by -1.

$$x=\frac{-1}{-1}$$

Divide -1 by -1 to get 1.

$$x=1$$

The system is now solved.

$$y=3 x=1$$