\left\{ \begin{array} { l } { y = 1 } \\ { y = 3 x - 2 } \end{array} \right.
Solve for y, x
x=1
y=1
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\left\{ \begin{array} { l } { y = 1 } \\ { y = 3 x - 2 } \end{array} \right.
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1=3x-2
Consider the second equation. Insert the known values of variables into the equation.
3x-2=1
Swap sides so that all variable terms are on the left hand side.
3x=1+2
Add 2 to both sides.
3x=3
Add 1 and 2 to get 3.
x=\frac{3}{3}
Divide both sides by 3.
x=1
Divide 3 by 3 to get 1.
y=1 x=1
The system is now solved.
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