\left\{ \begin{array} { l } { x _ { 1 } - 8 x _ { 2 } = 3 } \\ { x _ { 2 } = 5 } \end{array} \right.
Solve for x_1, x_2
x_{1}=43
x_{2}=5
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x_{1}-8\times 5=3
Consider the first equation. Insert the known values of variables into the equation.
x_{1}-40=3
Multiply -8 and 5 to get -40.
x_{1}=3+40
Add 40 to both sides.
x_{1}=43
Add 3 and 40 to get 43.
x_{1}=43 x_{2}=5
The system is now solved.
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