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Solve for x_1, x_2, x_3
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2x_{1}=x_{2} 12x_{1}+15x_{2}+22x_{3}=200000 x_{1}+x_{2}+x_{3}=10000
Reorder the equations.
x_{2}=2x_{1}
Solve 2x_{1}=x_{2} for x_{2}.
12x_{1}+15\times 2x_{1}+22x_{3}=200000 x_{1}+2x_{1}+x_{3}=10000
Substitute 2x_{1} for x_{2} in the second and third equation.
x_{1}=\frac{100000}{21}-\frac{11}{21}x_{3} x_{3}=-3x_{1}+10000
Solve these equations for x_{1} and x_{3} respectively.
x_{3}=-3\left(\frac{100000}{21}-\frac{11}{21}x_{3}\right)+10000
Substitute \frac{100000}{21}-\frac{11}{21}x_{3} for x_{1} in the equation x_{3}=-3x_{1}+10000.
x_{3}=7500
Solve x_{3}=-3\left(\frac{100000}{21}-\frac{11}{21}x_{3}\right)+10000 for x_{3}.
x_{1}=\frac{100000}{21}-\frac{11}{21}\times 7500
Substitute 7500 for x_{3} in the equation x_{1}=\frac{100000}{21}-\frac{11}{21}x_{3}.
x_{1}=\frac{2500}{3}
Calculate x_{1} from x_{1}=\frac{100000}{21}-\frac{11}{21}\times 7500.
x_{2}=2\times \frac{2500}{3}
Substitute \frac{2500}{3} for x_{1} in the equation x_{2}=2x_{1}.
x_{2}=\frac{5000}{3}
Calculate x_{2} from x_{2}=2\times \frac{2500}{3}.
x_{1}=\frac{2500}{3} x_{2}=\frac{5000}{3} x_{3}=7500
The system is now solved.