\left\{ \begin{array} { l } { x - 4 y + z = - 16 } \\ { y - 3 z = 9 } \\ { 3 y - 2 z = 160 } \end{array} \right.
Solve for x, y, z
x=229
y=66
z=19
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x=4y-z-16
Solve x-4y+z=-16 for x.
y=9+3z z=\frac{3}{2}y-80
Solve the second equation for y and the third equation for z.
z=\frac{3}{2}\left(9+3z\right)-80
Substitute 9+3z for y in the equation z=\frac{3}{2}y-80.
z=19
Solve z=\frac{3}{2}\left(9+3z\right)-80 for z.
y=9+3\times 19
Substitute 19 for z in the equation y=9+3z.
y=66
Calculate y from y=9+3\times 19.
x=4\times 66-19-16
Substitute 66 for y and 19 for z in the equation x=4y-z-16.
x=229
Calculate x from x=4\times 66-19-16.
x=229 y=66 z=19
The system is now solved.
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