Solve {l}{x=7}{y=-2x^2+29x+3}

$$\left\{ \begin{array} { l } { x = 7 } \\ { y = - 2 x ^ { 2 } + 29 x + 3 } \end{array} \right.$$

Solve for x, y

$$x=7$$

$$y=108$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$y=-2\times 7^{2}+29\times 7+3$$

Calculate 7 to the power of 2 and get 49.

$$y=-2\times 49+29\times 7+3$$

Multiply -2 and 49 to get -98.

$$y=-98+29\times 7+3$$

Multiply 29 and 7 to get 203.

$$y=-98+203+3$$

Add -98 and 203 to get 105.

$$y=105+3$$

Add 105 and 3 to get 108.

$$y=108$$

The system is now solved.

$$x=7 y=108$$