\left\{ \begin{array} { l } { x = 3 x } \\ { x + 2 y = 15 } \end{array} \right.
Solve for x, y
x=0
y = \frac{15}{2} = 7\frac{1}{2} = 7.5
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x-3x=0
Consider the first equation. Subtract 3x from both sides.
-2x=0
Combine x and -3x to get -2x.
x=0
Divide both sides by -2. Zero divided by any non-zero number gives zero.
0+2y=15
Consider the second equation. Insert the known values of variables into the equation.
2y=15
Anything plus zero gives itself.
y=\frac{15}{2}
Divide both sides by 2.
x=0 y=\frac{15}{2}
The system is now solved.
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