\left\{ \begin{array} { l } { x = 3 } \\ { 7 y - x = 11 } \end{array} \right.
Solve for x, y
x=3
y=2
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\left\{ \begin{array} { l } { x = 3 } \\ { 7 y - x = 11 } \end{array} \right.
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7y-3=11
Consider the second equation. Insert the known values of variables into the equation.
7y=11+3
Add 3 to both sides.
7y=14
Add 11 and 3 to get 14.
y=\frac{14}{7}
Divide both sides by 7.
y=2
Divide 14 by 7 to get 2.
x=3 y=2
The system is now solved.
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