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y-3y=-10
Consider the second equation. Subtract 3y from both sides.
-2y=-10
Combine y and -3y to get -2y.
y=\frac{-10}{-2}
Divide both sides by -2.
y=5
Divide -10 by -2 to get 5.
x=2\times 5
Consider the first equation. Insert the known values of variables into the equation.
x=10
Multiply 2 and 5 to get 10.
x=10 y=5
The system is now solved.