\left\{ \begin{array} { l } { x = 10 } \\ { x ^ { 2 } + 2 y = 5 } \end{array} \right.
Solve for x, y
x=10
y = -\frac{95}{2} = -47\frac{1}{2} = -47.5
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10^{2}+2y=5
Consider the second equation. Insert the known values of variables into the equation.
100+2y=5
Calculate 10 to the power of 2 and get 100.
2y=5-100
Subtract 100 from both sides.
2y=-95
Subtract 100 from 5 to get -95.
y=-\frac{95}{2}
Divide both sides by 2.
x=10 y=-\frac{95}{2}
The system is now solved.
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