\left\{ \begin{array} { l } { x + y - 2 = 0 } \\ { 3 x - 4 = 0 } \end{array} \right.
Solve for x, y
x = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333
y=\frac{2}{3}\approx 0.666666667
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3x=4
Consider the second equation. Add 4 to both sides. Anything plus zero gives itself.
x=\frac{4}{3}
Divide both sides by 3.
\frac{4}{3}+y-2=0
Consider the first equation. Insert the known values of variables into the equation.
-\frac{2}{3}+y=0
Subtract 2 from \frac{4}{3} to get -\frac{2}{3}.
y=\frac{2}{3}
Add \frac{2}{3} to both sides. Anything plus zero gives itself.
x=\frac{4}{3} y=\frac{2}{3}
The system is now solved.
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