\left\{ \begin{array} { l } { x + y = 50 } \\ { 3 y = 120 } \\ { x + z = 35 } \end{array} \right.
Solve for x, y, z
x=10
y=40
z=25
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y=\frac{120}{3}
Consider the second equation. Divide both sides by 3.
y=40
Divide 120 by 3 to get 40.
x+40=50
Consider the first equation. Insert the known values of variables into the equation.
x=50-40
Subtract 40 from both sides.
x=10
Subtract 40 from 50 to get 10.
10+z=35
Consider the third equation. Insert the known values of variables into the equation.
z=35-10
Subtract 10 from both sides.
z=25
Subtract 10 from 35 to get 25.
x=10 y=40 z=25
The system is now solved.
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