Solve {l}{x+y=36}{5/7=x/4}

$$\left\{ \begin{array} { l } { x + y = 36 } \\ { \frac { 5 } { 7 } = \frac { x } { 4 } } \end{array} \right.$$

Solve for x, y

$$x = \frac{20}{7} = 2\frac{6}{7} \approx 2.857142857$$

$$y = \frac{232}{7} = 33\frac{1}{7} \approx 33.142857143$$

Solution Steps

Consider the second equation. Multiply both sides by 4.

$$\frac{5}{7}\times 4=x$$

Multiply \frac{5}{7} and 4 to get \frac{20}{7}.

$$\frac{20}{7}=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=\frac{20}{7}$$

Consider the first equation. Insert the known values of variables into the equation.

$$\frac{20}{7}+y=36$$

Subtract \frac{20}{7} from both sides.

$$y=36-\frac{20}{7}$$

Subtract \frac{20}{7} from 36 to get \frac{232}{7}.

$$y=\frac{232}{7}$$

The system is now solved.

$$x=\frac{20}{7} y=\frac{232}{7}$$