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\frac{2}{5}x-\frac{3}{8}x=-5
Consider the second equation. Subtract \frac{3}{8}x from both sides.
\frac{1}{40}x=-5
Combine \frac{2}{5}x and -\frac{3}{8}x to get \frac{1}{40}x.
x=-5\times 40
Multiply both sides by 40, the reciprocal of \frac{1}{40}.
x=-200
Multiply -5 and 40 to get -200.
-200+y=220
Consider the first equation. Insert the known values of variables into the equation.
y=220+200
Add 200 to both sides.
y=420
Add 220 and 200 to get 420.
x=-200 y=420
The system is now solved.