Solve {l}{x+y+z=4000}{x+y=1600}{y=300}

$$\left\{ \begin{array} { l } { x + y + z = 4000 } \\ { x + y = 1600 } \\ { y = 300 } \end{array} \right.$$

Solve for x, y, z

$$x=1300$$

$$y=300$$

$$z=2400$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$x+300=1600$$

Subtract 300 from both sides.

$$x=1600-300$$

Subtract 300 from 1600 to get 1300.

$$x=1300$$

Consider the first equation. Insert the known values of variables into the equation.

$$1300+300+z=4000$$

Add 1300 and 300 to get 1600.

$$1600+z=4000$$

Subtract 1600 from both sides.

$$z=4000-1600$$

Subtract 1600 from 4000 to get 2400.

$$z=2400$$

The system is now solved.

$$x=1300 y=300 z=2400$$