\left\{ \begin{array} { l } { x + 4 y = - 6 } \\ { 3 y - y = 8 } \end{array} \right.
Solve for x, y
x=-22
y=4
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2y=8
Consider the second equation. Combine 3y and -y to get 2y.
y=\frac{8}{2}
Divide both sides by 2.
y=4
Divide 8 by 2 to get 4.
x+4\times 4=-6
Consider the first equation. Insert the known values of variables into the equation.
x+16=-6
Multiply 4 and 4 to get 16.
x=-6-16
Subtract 16 from both sides.
x=-22
Subtract 16 from -6 to get -22.
x=-22 y=4
The system is now solved.
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