\left\{ \begin{array} { l } { x + 4 = 9 } \\ { 3 x + y = 0 } \end{array} \right.
Solve for x, y
x=5
y=-15
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x=9-4
Consider the first equation. Subtract 4 from both sides.
x=5
Subtract 4 from 9 to get 5.
3\times 5+y=0
Consider the second equation. Insert the known values of variables into the equation.
15+y=0
Multiply 3 and 5 to get 15.
y=-15
Subtract 15 from both sides. Anything subtracted from zero gives its negation.
x=5 y=-15
The system is now solved.
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