Solve {l}{x+4=2}{y+12=74}{x+y-z=1}

$$\left\{ \begin{array} { l } { x + 4 = 2 } \\ { y + 12 = 74 } \\ { x + y - z = 1 } \end{array} \right.$$

Solve for x, y, z

$$x=-2$$

$$y=62$$

$$z=59$$

Solution Steps

Consider the first equation. Subtract 4 from both sides.

$$x=2-4$$

Subtract 4 from 2 to get -2.

$$x=-2$$

Consider the second equation. Subtract 12 from both sides.

$$y=74-12$$

Subtract 12 from 74 to get 62.

$$y=62$$

Consider the third equation. Insert the known values of variables into the equation.

$$-2+62-z=1$$

Add -2 and 62 to get 60.

$$60-z=1$$

Subtract 60 from both sides.

$$-z=1-60$$

Subtract 60 from 1 to get -59.

$$-z=-59$$

Divide both sides by -1.

$$z=\frac{-59}{-1}$$

Fraction \frac{-59}{-1} can be simplified to 59 by removing the negative sign from both the numerator and the denominator.

$$z=59$$

The system is now solved.

$$x=-2 y=62 z=59$$