\left\{ \begin{array} { l } { x + 3 y + 15 = 0 } \\ { x = - 3 } \end{array} \right.
Solve for x, y
x=-3
y=-4
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-3+3y+15=0
Consider the first equation. Insert the known values of variables into the equation.
12+3y=0
Add -3 and 15 to get 12.
3y=-12
Subtract 12 from both sides. Anything subtracted from zero gives its negation.
y=\frac{-12}{3}
Divide both sides by 3.
y=-4
Divide -12 by 3 to get -4.
x=-3 y=-4
The system is now solved.
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