\left\{ \begin{array} { l } { x + 3 = 5 } \\ { y = 3 x - 1 } \end{array} \right.
Solve for x, y
x=2
y=5
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x=5-3
Consider the first equation. Subtract 3 from both sides.
x=2
Subtract 3 from 5 to get 2.
y=3\times 2-1
Consider the second equation. Insert the known values of variables into the equation.
y=6-1
Multiply 3 and 2 to get 6.
y=5
Subtract 1 from 6 to get 5.
x=2 y=5
The system is now solved.
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