\left\{ \begin{array} { l } { x + 3 = 4 } \\ { 5 + y = 6 } \end{array} \right.
Solve for x, y
x=1
y=1
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x=4-3
Consider the first equation. Subtract 3 from both sides.
x=1
Subtract 3 from 4 to get 1.
y=6-5
Consider the second equation. Subtract 5 from both sides.
y=1
Subtract 5 from 6 to get 1.
x=1 y=1
The system is now solved.
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