Solve {l}{x+2y-4=0}{2y-3=0}

$$\left\{ \begin{array} { l } { x + 2 y - 4 = 0 } \\ { 2 y - 3 = 0 } \end{array} \right.$$

Solve for x, y

$$x=1$$

$$y = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Solution Steps

Consider the second equation. Add 3 to both sides. Anything plus zero gives itself.

$$2y=3$$

Divide both sides by 2.

$$y=\frac{3}{2}$$

Consider the first equation. Insert the known values of variables into the equation.

$$x+2\times \frac{3}{2}-4=0$$

Multiply 2 and \frac{3}{2} to get 3.

$$x+3-4=0$$

Subtract 4 from 3 to get -1.

$$x-1=0$$

Add 1 to both sides. Anything plus zero gives itself.

$$x=1$$

The system is now solved.

$$x=1 y=\frac{3}{2}$$