\left\{ \begin{array} { l } { x + 1 = 5 } \\ { 2 x + 3 y = 18 } \end{array} \right.
Solve for x, y
x=4
y = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333
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x=5-1
Consider the first equation. Subtract 1 from both sides.
x=4
Subtract 1 from 5 to get 4.
2\times 4+3y=18
Consider the second equation. Insert the known values of variables into the equation.
8+3y=18
Multiply 2 and 4 to get 8.
3y=18-8
Subtract 8 from both sides.
3y=10
Subtract 8 from 18 to get 10.
y=\frac{10}{3}
Divide both sides by 3.
x=4 y=\frac{10}{3}
The system is now solved.
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