Solve {l}{x+0.02y=15}{0.02y/15=0.4}

$$\left\{ \begin{array} { l } { x + 0.02 y = 15 } \\ { \frac { 0.02 y } { 15 } = 0.4 } \end{array} \right.$$

Solve for x, y

$$x=9$$

$$y=300$$

Solution Steps

Consider the second equation. Multiply both sides by 15.

$$0.02y=0.4\times 15$$

Multiply 0.4 and 15 to get 6.

$$0.02y=6$$

Divide both sides by 0.02.

$$y=\frac{6}{0.02}$$

Expand \frac{6}{0.02} by multiplying both numerator and the denominator by 100.

$$y=\frac{600}{2}$$

Divide 600 by 2 to get 300.

$$y=300$$

Consider the first equation. Insert the known values of variables into the equation.

$$x+0.02\times 300=15$$

Multiply 0.02 and 300 to get 6.

$$x+6=15$$

Subtract 6 from both sides.

$$x=15-6$$

Subtract 6 from 15 to get 9.

$$x=9$$

The system is now solved.

$$x=9 y=300$$