\left\{ \begin{array} { l } { k m + k + 1 = n + 3 } \\ { k m + 2 k + 1 = 2 n - 1 } \end{array} \right.
Solve for k, m, n
k=\frac{6}{m}\text{, }m\in \mathrm{R}\setminus 0,-1\text{, }n=4+\frac{6}{m}
k=-6\text{, }m=-1\text{, }n=-2
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