\left\{ \begin{array} { l } { b _ { 1 } + 3 d = 4 } \\ { 3 b _ { 1 } + 3 d = b _ { 11 } } \end{array} \right.
Solve for b_1, d, b_11
b_{1}=\frac{b_{11}}{2}-2
d=-\frac{b_{11}}{6}+2
b_{11}\in \mathrm{R}
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