\left\{ \begin{array} { l } { b = - 6 } \\ { c = 1 } \\ { - b / 2 a = - 3 } \end{array} \right.
Solve for b, c, a
b=-6
c=1
a=-1
Quiz
\left\{ \begin{array} { l } { b = - 6 } \\ { c = 1 } \\ { - b / 2 a = - 3 } \end{array} \right.
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\frac{-\left(-6\right)}{2}a=-3
Consider the third equation. Insert the known values of variables into the equation.
\left(-\left(-6\right)\right)a=-6
Multiply both sides of the equation by 2.
6a=-6
The opposite of -6 is 6.
a=\frac{-6}{6}
Divide both sides by 6.
a=-1
Divide -6 by 6 to get -1.
b=-6 c=1 a=-1
The system is now solved.
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