\left\{ \begin{array} { l } { a - 1 = b } \\ { a = 3 } \end{array} \right.
Solve for a, b
a=3
b=2
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\left\{ \begin{array} { l } { a - 1 = b } \\ { a = 3 } \end{array} \right.
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3-1=b
Consider the first equation. Insert the known values of variables into the equation.
2=b
Subtract 1 from 3 to get 2.
b=2
Swap sides so that all variable terms are on the left hand side.
a=3 b=2
The system is now solved.
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