\left\{ \begin{array} { l } { a + b = 28 } \\ { 2 a + 3 = 7 } \end{array} \right.
Solve for a, b
a=2
b=26
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2a=7-3
Consider the second equation. Subtract 3 from both sides.
2a=4
Subtract 3 from 7 to get 4.
a=\frac{4}{2}
Divide both sides by 2.
a=2
Divide 4 by 2 to get 2.
2+b=28
Consider the first equation. Insert the known values of variables into the equation.
b=28-2
Subtract 2 from both sides.
b=26
Subtract 2 from 28 to get 26.
a=2 b=26
The system is now solved.
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