\left\{ \begin{array} { l } { C = 3 } \\ { 4 a + 2 b + 3 = 3 } \\ { 9 a + 3 b + 3 = 9 } \end{array} \right.
Solve for C, a, b
C=3
a=2
b=-4
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a=-\frac{1}{2}b b=2-3a
Solve the second equation for a and the third equation for b.
b=2-3\left(-\frac{1}{2}\right)b
Substitute -\frac{1}{2}b for a in the equation b=2-3a.
b=-4
Solve b=2-3\left(-\frac{1}{2}\right)b for b.
a=-\frac{1}{2}\left(-4\right)
Substitute -4 for b in the equation a=-\frac{1}{2}b.
a=2
Calculate a from a=-\frac{1}{2}\left(-4\right).
C=3 a=2 b=-4
The system is now solved.
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