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Solve for a, b, c
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c=-3 a+b+c=0 9a-3b+c=0
Reorder the equations.
a+b-3=0 9a-3b-3=0
Substitute -3 for c in the second and third equation.
b=-a+3 a=\frac{1}{3}+\frac{1}{3}b
Solve these equations for b and a respectively.
a=\frac{1}{3}+\frac{1}{3}\left(-a+3\right)
Substitute -a+3 for b in the equation a=\frac{1}{3}+\frac{1}{3}b.
a=1
Solve a=\frac{1}{3}+\frac{1}{3}\left(-a+3\right) for a.
b=-1+3
Substitute 1 for a in the equation b=-a+3.
b=2
Calculate b from b=-1+3.
a=1 b=2 c=-3
The system is now solved.