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Solve for a, b, c
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c=3 9a+3b+c=0 a-b+c=0
Reorder the equations.
9a+3b+3=0 a-b+3=0
Substitute 3 for c in the second and third equation.
b=-1-3a a=b-3
Solve these equations for b and a respectively.
a=-1-3a-3
Substitute -1-3a for b in the equation a=b-3.
a=-1
Solve a=-1-3a-3 for a.
b=-1-3\left(-1\right)
Substitute -1 for a in the equation b=-1-3a.
b=2
Calculate b from b=-1-3\left(-1\right).
a=-1 b=2 c=3
The system is now solved.