\left\{ \begin{array} { l } { 8 z + 9 o - b + c = 0 } \\ { 26 + a + 5 b + c = 0 } \\ { 104 + 10 a + 2 b + c = 0 } \end{array} \right.
Solve for z, o, b, c, a
z=\frac{19b}{24}-\frac{9o}{8}+\frac{13}{6}
o\in \mathrm{R}
b\in \mathrm{R}
c=\frac{-16b-52}{3}
a=\frac{b-26}{3}
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