\left\{ \begin{array} { l } { 8 - a = 5 } \\ { - 10 + b = - 6 } \end{array} \right.
Solve for a, b
a=3
b=4
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-a=5-8
Consider the first equation. Subtract 8 from both sides.
-a=-3
Subtract 8 from 5 to get -3.
a=\frac{-3}{-1}
Divide both sides by -1.
a=3
Fraction \frac{-3}{-1} can be simplified to 3 by removing the negative sign from both the numerator and the denominator.
b=-6+10
Consider the second equation. Add 10 to both sides.
b=4
Add -6 and 10 to get 4.
a=3 b=4
The system is now solved.
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