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Solve for s, t
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8-3s=0
Consider the first equation. Add 7 and 1 to get 8.
-3s=-8
Subtract 8 from both sides. Anything subtracted from zero gives its negation.
s=\frac{-8}{-3}
Divide both sides by -3.
s=\frac{8}{3}
Fraction \frac{-8}{-3} can be simplified to \frac{8}{3} by removing the negative sign from both the numerator and the denominator.
4t-5\times \frac{8}{3}=-17
Consider the second equation. Insert the known values of variables into the equation.
4t-\frac{40}{3}=-17
Multiply -5 and \frac{8}{3} to get -\frac{40}{3}.
4t=-17+\frac{40}{3}
Add \frac{40}{3} to both sides.
4t=-\frac{11}{3}
Add -17 and \frac{40}{3} to get -\frac{11}{3}.
t=\frac{-\frac{11}{3}}{4}
Divide both sides by 4.
t=\frac{-11}{3\times 4}
Express \frac{-\frac{11}{3}}{4} as a single fraction.
t=\frac{-11}{12}
Multiply 3 and 4 to get 12.
t=-\frac{11}{12}
Fraction \frac{-11}{12} can be rewritten as -\frac{11}{12} by extracting the negative sign.
s=\frac{8}{3} t=-\frac{11}{12}
The system is now solved.