\left\{ \begin{array} { l } { 6 - 2 x = 3 } \\ { 2 + 2 y = 3 } \end{array} \right.
Solve for x, y
x = \frac{3}{2} = 1\frac{1}{2} = 1.5
y=\frac{1}{2}=0.5
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-2x=3-6
Consider the first equation. Subtract 6 from both sides.
-2x=-3
Subtract 6 from 3 to get -3.
x=\frac{-3}{-2}
Divide both sides by -2.
x=\frac{3}{2}
Fraction \frac{-3}{-2} can be simplified to \frac{3}{2} by removing the negative sign from both the numerator and the denominator.
2y=3-2
Consider the second equation. Subtract 2 from both sides.
2y=1
Subtract 2 from 3 to get 1.
y=\frac{1}{2}
Divide both sides by 2.
x=\frac{3}{2} y=\frac{1}{2}
The system is now solved.
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Integration
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Limits
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