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3+4x=6
Consider the first equation. Swap sides so that all variable terms are on the left hand side.
4x=6-3
Subtract 3 from both sides.
4x=3
Subtract 3 from 6 to get 3.
x=\frac{3}{4}
Divide both sides by 4.
7+2y=9
Consider the second equation. Swap sides so that all variable terms are on the left hand side.
2y=9-7
Subtract 7 from both sides.
2y=2
Subtract 7 from 9 to get 2.
y=\frac{2}{2}
Divide both sides by 2.
y=1
Divide 2 by 2 to get 1.
x=\frac{3}{4} y=1
The system is now solved.