\left\{ \begin{array} { l } { 5 x + 6 y = 0 } \\ { y = 1 } \end{array} \right.
Solve for x, y
x = -\frac{6}{5} = -1\frac{1}{5} = -1.2
y=1
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5x+6\times 1=0
Consider the first equation. Insert the known values of variables into the equation.
5x+6=0
Multiply 6 and 1 to get 6.
5x=-6
Subtract 6 from both sides. Anything subtracted from zero gives its negation.
x=-\frac{6}{5}
Divide both sides by 5.
x=-\frac{6}{5} y=1
The system is now solved.
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