Solve {l}{5x+5=0}{6x-3y=0}

$$\left\{ \begin{array} { l } { 5 x + 5 = 0 } \\ { 6 x - 3 y = 0 } \end{array} \right.$$

Solve for x, y

$$x=-1$$

$$y=-2$$

Solution Steps

Consider the first equation. Subtract 5 from both sides. Anything subtracted from zero gives its negation.

$$5x=-5$$

Divide both sides by 5.

$$x=\frac{-5}{5}$$

Divide -5 by 5 to get -1.

$$x=-1$$

Consider the second equation. Insert the known values of variables into the equation.

$$6\left(-1\right)-3y=0$$

Multiply 6 and -1 to get -6.

$$-6-3y=0$$

Add 6 to both sides. Anything plus zero gives itself.

$$-3y=6$$

Divide both sides by -3.

$$y=\frac{6}{-3}$$

Divide 6 by -3 to get -2.

$$y=-2$$

The system is now solved.

$$x=-1 y=-2$$