Solve {l}{40=b}{400=60a+b}

$$\left\{ \begin{array} { l } { 40 = b } \\ { 400 = 60 a + b } \end{array} \right.$$

Solve for b, a

$$b=40$$

$$a=6$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$b=40$$

Consider the second equation. Insert the known values of variables into the equation.

$$400=60a+40$$

Swap sides so that all variable terms are on the left hand side.

$$60a+40=400$$

Subtract 40 from both sides.

$$60a=400-40$$

Subtract 40 from 400 to get 360.

$$60a=360$$

Divide both sides by 60.

$$a=\frac{360}{60}$$

Divide 360 by 60 to get 6.

$$a=6$$

The system is now solved.

$$b=40 a=6$$