\left\{ \begin{array} { l } { 4 x - 2 y - 7 x = - 1 } \\ { 12 x + 12 y - 7 x - 12 y = 15 } \end{array} \right.
Solve for x, y
x=3
y=-4
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-3x-2y=-1
Consider the first equation. Combine 4x and -7x to get -3x.
5x+12y-12y=15
Consider the second equation. Combine 12x and -7x to get 5x.
5x=15
Combine 12y and -12y to get 0.
x=\frac{15}{5}
Divide both sides by 5.
x=3
Divide 15 by 5 to get 3.
-3\times 3-2y=-1
Consider the first equation. Insert the known values of variables into the equation.
-9-2y=-1
Multiply -3 and 3 to get -9.
-2y=-1+9
Add 9 to both sides.
-2y=8
Add -1 and 9 to get 8.
y=\frac{8}{-2}
Divide both sides by -2.
y=-4
Divide 8 by -2 to get -4.
x=3 y=-4
The system is now solved.
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