\left\{ \begin{array} { l } { 4 x + 2 = 2 } \\ { 3 x - 2 y = 1 } \end{array} \right.
Solve for x, y
x=0
y=-\frac{1}{2}=-0.5
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4x=2-2
Consider the first equation. Subtract 2 from both sides.
4x=0
Subtract 2 from 2 to get 0.
x=0
Divide both sides by 4. Zero divided by any non-zero number gives zero.
3\times 0-2y=1
Consider the second equation. Insert the known values of variables into the equation.
0-2y=1
Multiply 3 and 0 to get 0.
-2y=1
Anything plus zero gives itself.
y=-\frac{1}{2}
Divide both sides by -2.
x=0 y=-\frac{1}{2}
The system is now solved.
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Limits
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