\left\{ \begin{array} { l } { 4 + y = 0 } \\ { x + 2 = 1 } \end{array} \right.
Solve for y, x
x=-1
y=-4
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y=-4
Consider the first equation. Subtract 4 from both sides. Anything subtracted from zero gives its negation.
x=1-2
Consider the second equation. Subtract 2 from both sides.
x=-1
Subtract 2 from 1 to get -1.
y=-4 x=-1
The system is now solved.
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