\left\{ \begin{array} { l } { 3 x = 6 } \\ { 2 x + y = 1 } \end{array} \right.
Solve for x, y
x=2
y=-3
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x=\frac{6}{3}
Consider the first equation. Divide both sides by 3.
x=2
Divide 6 by 3 to get 2.
2\times 2+y=1
Consider the second equation. Insert the known values of variables into the equation.
4+y=1
Multiply 2 and 2 to get 4.
y=1-4
Subtract 4 from both sides.
y=-3
Subtract 4 from 1 to get -3.
x=2 y=-3
The system is now solved.
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