\left\{ \begin{array} { l } { 3 x + y = 5 } \\ { 53 + x = 10 } \end{array} \right.
Solve for x, y
x=-43
y=134
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x=10-53
Consider the second equation. Subtract 53 from both sides.
x=-43
Subtract 53 from 10 to get -43.
3\left(-43\right)+y=5
Consider the first equation. Insert the known values of variables into the equation.
-129+y=5
Multiply 3 and -43 to get -129.
y=5+129
Add 129 to both sides.
y=134
Add 5 and 129 to get 134.
x=-43 y=134
The system is now solved.
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