Solve {l}{3x+y=1}{6x=3}

$$\left\{ \begin{array} { l } { 3 x + y = 1 } \\ { 6 x = 3 } \end{array} \right.$$

Solve for x, y

$$x=\frac{1}{2}=0.5$$

$$y=-\frac{1}{2}=-0.5$$

Solution Steps

Consider the second equation. Divide both sides by 6.

$$x=\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$x=\frac{1}{2}$$

Consider the first equation. Insert the known values of variables into the equation.

$$3\times \frac{1}{2}+y=1$$

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$\frac{3}{2}+y=1$$

Subtract \frac{3}{2} from both sides.

$$y=1-\frac{3}{2}$$

Subtract \frac{3}{2} from 1 to get -\frac{1}{2}.

$$y=-\frac{1}{2}$$

The system is now solved.

$$x=\frac{1}{2} y=-\frac{1}{2}$$